B 0 ¯ = μ 0 I π R ( R 2 − a 2 R + arcsin a R ) . {\displaystyle {\overline {B_{0}}}={\frac {\mu _{0}I}{\pi R}}({\frac {\sqrt {R^{2}-a^{2}}}{R}}+\arcsin {\frac {a}{R}}).}
B = 4 π I N μ 1 μ 2 c ( 2 d μ 1 μ 2 + L 2 − d ) ( μ 1 + μ 2 ) ) . {\displaystyle B={\frac {4\pi IN\mu _{1}\mu _{2}}{c(2d\mu _{1}\mu _{2}+{\frac {L}{2}}-d)(\mu _{1}+\mu _{2}))}}.} k 1 , k 2 {\displaystyle k_{1},k_{2}} s g n ( k 1 ) = 1 , s g n ( k 2 ) = − 1 , | k 1 | < | k 2 | {\displaystyle sgn(k_{1})=1,sgn(k_{2})=-1,|k_{1}|<|k_{2}|} к примеру k1=1, k2=-20. k 1 {\displaystyle k_{1}} k 2 {\displaystyle k_{2}} H = ∏ i = 1 n ( 1 + H i ) − 1 {\displaystyle H=\prod _{i=1}^{n}(1+H_{i})-1} H = ∏ i = 1 n ( 1 + H i ) − 1 {\displaystyle H=\prod _{i=1}^{n}(1+H_{i})-1} H i {\displaystyle H_{i}} H 0 = ( 1.065 ) n − 1 {\displaystyle H_{0}=(1.065)^{n}-1} E x p e c t e d = P o s i t i v e / ( H + 1 ) {\displaystyle Expected=Positive/(H+1)} E x p e c t e d = ( 1 , 04121 n ) ⋅ x ⋅ k 1 + ( n ⋅ 0.0001 ) ⋅ ( 0.9389 n ) ⋅ x ⋅ k 2 {\displaystyle Expected=(1,04121^{n})\cdot x\cdot k_{1}+(n\cdot 0.0001)\cdot (0.9389^{n})\cdot x\cdot k_{2}} P o s i t i v e = ( 0.9999 n ) ⋅ ( ( 1.109 n ) ⋅ x ) ⋅ k 1 + ( 1 − 0.9999 n ) ⋅ k 2 ⋅ x {\displaystyle Positive=(0.9999^{n})\cdot ((1.109^{n})\cdot x)\cdot k_{1}+(1-0.9999^{n})\cdot k_{2}\cdot x} P o s i t i v e = ( 0.99999 n ) ⋅ ( ( 1.126 n ) ⋅ x ) ⋅ k 1 + ( n ⋅ 0.00001 ) ⋅ k 2 ⋅ x {\displaystyle Positive=(0.99999^{n})\cdot ((1.126^{n})\cdot x)\cdot k_{1}+(n\cdot 0.00001)\cdot k_{2}\cdot x} E x p e c t e d = ( 1.0572 n ) ⋅ x ⋅ k 1 + ( 1 − 0.99999 n ) ⋅ ( 0.9389 n ) ⋅ x ⋅ k 2 ; {\displaystyle Expected=(1.0572^{n})\cdot x\cdot k_{1}+(1-0.99999^{n})\cdot (0.9389^{n})\cdot x\cdot k_{2};} P o s i t i v e = ( 0.9 n ) ⋅ ( ( 1.23 n ) ⋅ x ) ⋅ k 1 + ( 1 − 0.9 n ) ⋅ k 2 ⋅ x {\displaystyle Positive=(0.9^{n})\cdot ((1.23^{n})\cdot x)\cdot k_{1}+(1-0.9^{n})\cdot k_{2}\cdot x} E x p e c t e d = P o s i t i v e ⋅ ( 0.9389 n ) {\displaystyle Expected=Positive\cdot (0.9389^{n})} E x p e c t e d = ( 0.9 n ) ⋅ ( ( 1.23 n ) ⋅ x ) ⋅ k 1 + ( 1 − 0.9 n ) ⋅ k 2 ⋅ ( 0.9389 n ) {\displaystyle Expected=(0.9^{n})\cdot ((1.23^{n})\cdot x)\cdot k_{1}+(1-0.9^{n})\cdot k_{2}\cdot (0.9389^{n})} {\displaystyle } E b = ( 1 , 04121 n ) ⋅ x ⋅ k 1 + ( n ⋅ 0.0001 ) ⋅ ( 0.9389 n ) ⋅ x ⋅ k 2 {\displaystyle E_{b}=(1,04121^{n})\cdot x\cdot k_{1}+(n\cdot 0.0001)\cdot (0.9389^{n})\cdot x\cdot k_{2}} E n = ( 1.0572 n ) ⋅ x ⋅ k 1 + ( 1 − 0.99999 n ) ⋅ ( 0.9389 n ) ⋅ x ⋅ k 2 ; {\displaystyle E_{n}=(1.0572^{n})\cdot x\cdot k_{1}+(1-0.99999^{n})\cdot (0.9389^{n})\cdot x\cdot k_{2};} E m = ( 0.9 n ) ⋅ ( ( 1.23 n ) ⋅ x ) ⋅ k 1 + ( 1 − 0.9 n ) ⋅ k 2 ⋅ ( 0.9389 n ) {\displaystyle E_{m}=(0.9^{n})\cdot ((1.23^{n})\cdot x)\cdot k_{1}+(1-0.9^{n})\cdot k_{2}\cdot (0.9389^{n})} {\displaystyle } {\displaystyle } {\displaystyle } {\displaystyle } {\displaystyle } {\displaystyle } {\displaystyle } {\displaystyle } {\displaystyle } {\displaystyle } {\displaystyle } {\displaystyle } {\displaystyle } {\displaystyle }